The LeetCode 17 solution, which tackles the “Letter Combination of a Phone Number” problem, is a popular challenge that tests both beginners and experienced coders. In this blog post, we will break down the solution step-by-step, making the process easy to understand and implement. Whether you’re new to coding or seeking a more efficient approach, this guide will walk you...
LeetCode 13 Solution: Roman to Integer in Python
When tackling coding challenges like LeetCode’s “Roman to Integer” problem (LeetCode 13), it’s essential to not only solve the problem but also understand the process behind it. In this post, we will walk through a complete LeetCode 13 solution with clear explanations. The goal is to convert a Roman numeral into an integer, using Python. Roman Numerals: What You Need to Know Roman...
LeetCode 12 Solution: Converting Integers to Roman Numerals
LeetCode 12 Solution presents one of the most interesting challenges by requiring the conversion of integers into Roman numerals. While the Roman numeral system may seem ancient, it offers a fascinating way to sharpen your algorithmic skills through its unique rules for converting numbers. The problem asks us to take an integer and convert it into its corresponding Roman numeral using a...
LeetCode #3 Solution: Longest Substring
LeetCode #3 Solution – Longest Substring Without Repeating Characters: The challenge is to find the length of the longest substring in a given string s that contains no repeating characters. A substring is a contiguous sequence of characters within a string. Examples: Input: s = “abcabcbb”Output: 3Explanation: The longest substring without repeating characters is...
LeetCode #1 solution: Two Sum
Problem: 1 two sum Leetcode #1 solution – Two Sum: Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return the answer in any order. Examples: Input: nums = [2...